人教版八年级上册数学第十一章11.2.2三角形的外角自主学习互动探究长江全能学案答案
1自主学习例1答案
∵ AD、BE是∠CAB与∠CBA的平分线
∴ ∠1 = 1/2∠BAC,∠2 = 1/2∠ABC
∴ ∠1 + ∠2 = 1/2(∠BAC + ∠ABC) = 45°
而∠ADE = ∠1 + ∠2
故,∠ADE = 45°
2自主学习例2答案
∵ ∠CEF = ∠AED = 48°,∠BCA = ∠CEF + ∠F,
∴ ∠F = ∠BCA - ∠CEF = 74° - 48° = 26°,
∴ ∠BDF = 180° - ∠B - ∠F = 180° - 67° - 26° = 87°
3互动探究第1题答案
D
4互动探究第2题答案
∠HAG = 1/2∠ACB,
理由如下:
如图11 - 5
∵ AD、BE、CF是△ABC的角平分线,
∴ ∠2 = 1/2∠ABC,∠1 = 1/2∠BAC,∠3 = 1/2∠ACB,
∵ ∠ABC + ∠BAC + ∠ACB = 180°,
∴ ∠1 + ∠2 + ∠3 = 90°,
∵ ∠AHG = ∠1 + ∠2,
∴ ∠AHG = 90° - ∠3,
∵ AG ⊥ BE,∴ ∠HAG = 90° - ∠AHG,
∴ ∠HAG = ∠3,
∴ ∠HAG = 1/2∠ACB